# The temperature of a block of iron, which has a specific heat of 450 j/(kg k), increases by 3 k when 2700 j of energy are added to it. what is the mass of this block of iron?

Jun 17, 2014

2.0 kg

The equation we need to use is: ∆Q=mc∆θ

The following data is given:
∆Q=2700
$c = 450 J k {g}^{-} 1 {K}^{-} 1$
∆θ=3K

Rearrange for mass and sub. in values:
m=(∆Q)/(c∆θ)=2700/(450×3)=2.0kg