Question

The temperature of a block of iron, which has a specific heat of 450 j/(kg k), increases by 3 k when 2700 j of energy are added to it. what is the mass of this block of iron?

Answer 1

2.0 kg

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The equation we need to use is: `∆Q=mc∆θ`

The following data is given:
`∆Q=2700`
`c=450 J kg^-1 K^-1`
`∆θ=3K`

Rearrange for mass and sub. in values:
`m=(∆Q)/(c∆θ)=2700/(450×3)=2.0kg`