In the reaction between sodium oxide and water, what mass of sodium oxide will be needed to produce 5.90g of sodium hydroxide ?

1 Answer
Apr 29, 2018

5.25"g"

Explanation:

First we need our balanced equation.

Na_2O + H_2O rarr 2NaOH

For this problem, we need to work backwards, finding moles of 2NaOH, then how many moles of Na_2O was required to make the 2NaOH, then convert that to grams.

First we find how many moles of 2NaOH are in 5.90g.

5.90"g" * "1mol"/"40.00g" = .148"g"

Then we check how many moles of Na_2O were required to produce it.

0.148"mol "Na_2O" * "1mol Na_2O"/"2"mol 2NaOH" = 0.0740"mol"

Then convert the moles to grams.

"0.0740mol" * 70.99"g/mol" = 5.25"g"