# Is 2pi*sqrt(l/g) reducable to a dimension of time?

Mar 18, 2016

Yes. Yes it is.

#### Explanation:

This equation is the period of a simple pendulum. Assuming your $l$ stands for length, and $g$ stands for gravity, we can rewrite this problem as

Period $= 2 \pi \cdot \sqrt{\frac{L}{\frac{L}{T} ^ 2}}$

Rewriting your fraction inside the $\sqrt{}$ symbol,

Period $= 2 \pi \cdot \sqrt{L \cdot {T}^{2} / L}$

Cancelling terms and knowing that square roots cancel powers of 2, we get,

Period $= 2 \pi \cdot T$

So yes, this equation is reducible to a unit of time.