Is #f(x)=(x-2)^2(x+1)# increasing or decreasing at #x=1#?

1 Answer
Mar 11, 2018

#f(x)" is decreasing at "x=1#

Explanation:

#"to determine if f(x) is increasing/decreasing at x = 1"#

#"differentiate f(x) and evaluate at x = 1"#

#• " if "f'(1)>0" then "f(x)" is increasing at x = 1"#

#• " if "f'(1)<0" then "f(x)" is decreasing at x = 1"#

#f(x)=(x-2)^2(x+1)larrcolor(blue)"expand factors"#

#color(white)(f(x))=x^3-3x^2+4#

#rArrf'(x)=3x^2-6x#

#rArrf'(1)=3-6=-3<0#

#"since" 'f'(1)<0" then "f(x)" is decreasing at x = 1"#
graph{(x-2)^2(x+1) [-10, 10, -5, 5]}