Is the the sequence 5a-1, 3a-1, a-2, -a-1,... arithmetic?

1 Answer
Dec 11, 2016

Interpretation 1: Assuming the question is with a- 2:

The common difference, d, of a sequence will determine whether it is arithmetic, geometric or neither. If it is arithmetic, the common difference will be a common number added or subtracted from the previous term.

d = t_2 - t_1

d = 3a - 1 - (5a - 1)

d = 3a - 1 - 5a + 1

d = -2a

d= t_3 - t_2

d = a - 2 - (3a - 1)

d = -2a - 1

Since the two numbers aren't the same, this sequence is not arithmetic

Interpretation 2: Assuming the question is with a - 1

Doing the same process as above:

d = t_2 - t_1

d = 3a - 1 - (5a - 1)

d = 3a - 1 - 5a + 1

d = -2a

d = t_3 - t_2

d = a - 1 -(3a - 1)

d = a - 1 - 3a + 1

d = -2a

Since the two d's are the same, this sequence is arithmetic.

Hopefully this helps!