It is desired to increase the volume of a given weight of co2 at40degrees to three times original volume at constant pressure the temperature should be raised a) 333b) 120c) 666 degrees?

2 Answers
Dec 25, 2017

Answer:

The answer is option #(c)=666^@C#

Explanation:

Apply Charles' Law

#V_1/T_1=V_2/T_2# at constant pressure

The initial volume is #V_1=Vu#

The final volume is #V_2=3Vu#

The initial temperature is #T_1=40^@C+273=313K#

The final temperature is

#T_2=V_2/V_1*T_1=3V/V*313=939K#

Therefore,

The temperature should be raised by #=939-273=666^@C#

Dec 25, 2017

Answer:

Using #PV=nRT#, the answer will be (c) #666^@"C"#.

Explanation:

According to the problem, pressure remains constants. Since the weight also is constant, the number of moles remains constant.

From the ideal gas equation, we can deduce that #P# is directly proportional to the absolute temperature.

#V_2/V_1 = T_2/T_1#

#3 = T_2/((40+273)"K")#

So

#T_2 = "939 K"#

#T_2= "939 K" - 273 = 666^@"C"#