# It is noted that 8% of kaplan students are left handed. If 20 students are randomly selected, how do you calculate the probability that none of them are left handed?

Nov 15, 2016

P(20 right handed students) $= 0.18869$

This is a probability of about 18.9%

#### Explanation:

P(left handed) = 8% = 0.08

P(right handed) = 1 - P(left handed) = $1 - 0.08 = 0.92$

For none of 20 students to be left handed, means they must all be right handed.

$P \left(R R R R \ldots \ldots R R R\right) \text{ } \leftarrow$ 20 times

=$0.92 \times 0.92 \times 0.92 \times \times 0.92 \text{ } \leftarrow$ 20 times

=${0.92}^{20}$

=$0.18869$

This is a probability of about 18.9%