Lead nitrate can be decomposed by heating. What is the percent yield of the decomposition reaction if 9.9 g of #Pb(NO_3)_2#are heated to give 5.5 g of #PbO#??

1 Answer
May 31, 2017

Answer:

#"Percentage yield"~=80%#

Explanation:

We need (i) a stoichiometric equation........

#Pb(NO_3)_2 +Delta rarr PbO(s)+2NO_2(g)+1/2O_2(g)#

This simply must be known; nitrates undergo thermal decomposition to give oxide and nitric oxide and dioxygen gas.

And (ii). given the 1:1 stoichiometry between nitrate and oxide, we needs equivalent quantities of lead oxide and lead nitrate:

#"Percentage yield"="Moles of lead oxide"/"Moles of lead nitrate"xx100%=#

#((5.5*g)/(223.2*g*mol^-1))/((9.9*g)/(331.2*g*mol^-1))xx100%=??%#