Let #f(x) = 1 /(x+3)# and #g(x) = -2 /x#, how do you find each of the compositions?

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Answer 1 · 2018-07-12T12:41:04

Please see the explanation below.

The functions are

#f(x)=1/(x+3)#

And

#g(x)=-2/x#

There are #2# compositions

#fog(x)=f(g(x))=f(-2/x)#

#=1/((-2/x)+3)#

#=x/(3x-2)#

And

#gof(x)=g(f(x))=g(1/(x+3))#

#=-2/(1/(x+3))#

#=-2(x+3)#

Therefore,

#fog(x)!=gof(x)#