Question

Let `f(x)=1-x` and `g(x)= x^2` and `h(x)= 1/x`, how do you find `f(g(x))`?

Answer 1

`f(g(x))=1-x^4`

Explanation:

Here ,

`f(x)=1-x and g(x)=x^2`

Now ,

`f(g(x))=f(x^2)to[becauseg(x)=x^2]`

`f(g(x))=1-(x^2)^2`

`f(g(x))=1-x^4`