# Let f(x) = 2- x^2 and g(x) = x^2 -2. How do you solve f(x) = g(x) ?

Sep 29, 2015

$x = \pm \sqrt{2}$

#### Explanation:

If $f \left(x\right) = g \left(x\right)$ then $2 - {x}^{2} = {x}^{2} - 2$

and $4 = 2 {x}^{2}$

$2 = {x}^{2}$

Therefore,

$x = \sqrt{2} , x = - \sqrt{2}$

Hope this helps :)