Let $f (x) = | x + 1 |$ $f(x) =abs(x+1)$ and g(x) = 3x-2 how do you find (fog)(x)?

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Answer 1 · 2015-12-20T16:49:35

Answer: $| 3 x - 1 |$ $|3x-1|$

$(f o g) (x) = f (g (x))$ $(fog)(x) = f(g(x))$

Which mean replace the g(x) into every "x" you see in the $f (x)$ $f(x)$ function.

$f (g (x)) = f (3 x - 2) = | (3 x - 2) + 1 |$ $f(g(x))= f(3x-2) = |(color(red)(3x-2))+1|$

$= | 3 x - 1 |$ $= |3x - 1|$

Let f(x) =abs(x+1)f(x)=|x+1|f(x) =abs(x+1) and g(x) = 3x-2 how do you find (fog)(x)?