Let #f(x) = sin(x)#. Find #f^400(x)# (the #400th# derivative of #f(x)#)?

2 Answers
Mar 10, 2017

#sin x#

Explanation:

We know that #e^(ix)=cosx+isinx# and

#sinx = "Im"(e^(ix))# now

#(d^n)/(dx^n) e^(ix)=i^n e^(ix)#

now if #n=400# we have #i^400=(i^4)^100=1#

so finally

#f^((400))(x)=sin x#

Mar 10, 2017

#f^400 (x) = sinx#

Explanation:

Here's another way.

We create a table with the n derivatives of #f(x)#.

#f(x) = sinx#
#f^1(x) = cosx#
#f^2(x) = -sinx#
#f^3(x) = -cosx#
#f^4(x) = sinx#

So, essentially, whenever you have a multiple of #4#, such as #400#, your derivative will be #sinx#.

Therefore, #f^400 (x) = sinx#.

Hopefully this helps!