Question

Let `f(x)=x^2-12` and `g(x)=15-x`, how do you find `(f/g)(5)`?

Answer 1

`(f/g)=1.3`

Explanation:

`f(x)=x^2-12`
`g(x)=15-x`
`(f/g)(5)`

`(f/g)(x)= (x^2-12)/(15-x)`

`(f/g)(5)=((5)^2-12)/(15-(5))`

`(f/g)(5)=(25-12)/(15-5)`

`(f/g)(5)=13/10`

`(f/g)(5)=1.3`