Question

Let `f(x)=x^2-4` and `g(x)=sqrtx+3`, how do you find f(g(x))?

Answer 1

`f(g(x))= x+6sqrtx+5`

Explanation:

`f(x)=x^2-4` and `g(x) =sqrtx +3`

`f(g(x)) = [g(x)]^2-4 = (sqrtx+3)^2-4`

`= (sqrtx+3)(sqrtx+3)-4= x+6sqrtx+9-4`

`= x+6sqrtx+5`