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Let $f(x)=x^2-4$ and $g(x)=sqrtx+3$ , how do you find g(f(x))?

1 Answer

Jun 28, 2016

$g(f(x))=sqrt(x^2-4)+3$

Explanation:

$g(f(x))=g(x^2-4)=sqrt(x^2-4)+3$

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