Let $f(x)=(x+3)^2$ and $g(x)=x+4$ , how do you find $h(x)=f(x)+g(x)$ ?

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Answer 1 · 2017-01-10T17:52:41

Substitute the right sides of equations for the two functions into the right side of the equation for $h(x)$ , expand the square, combine like terms.

Given: $f(x) = (x + 3)^2 and g(x) = x + 4$

$h(x) = f(x) + g(x)$

Substitute the right sides of the equations for the two functions into the right side of the equation for $h(x)$ :

$h(x) = (x+ 3)^2 + (x + 4)$

Expand the square:

$h(x) = x^2 + 6x + 9 + x + 4$

Combine like terms:

$h(x) = x^2 + 7x + 13$

Let f(x)=(x+3)^2f(x)=(x+3)^2 and g(x)=x+4g(x)=x+4, how do you find h(x)=f(x)+g(x)h(x)=f(x)+g(x)?