Question

Let `h(x)=6x^5-5x^4+4x^3-3x^2-2x+x+7` and `m(x)=x^2-1`, how do you find the quotient h(x) and m(x)?

Answer 1

`-6x^5+5x^4-3x^3+2x^2+x-7`

Explanation:

`h(x)=6x^5-5x^4+4x^3-3x^2-2x+x+7`
`m(x)=x^2-1`
therefore, `h(x)=(6x^5-5x^4+4x^3-3x^2-2x+x+7)/(x^2-1)`
=`-(6x^5-5x^4+3x^3-2x^2-x+1)`
=`-6x^5+5x^4-3x^3+2x^2+x+1`

simplify `(-2x+x)` and `(-3x^2 and x^2)`