# Lim (sin3t)/(sin2t) x-->0 how do we find it's limit?

##### 1 Answer

Jul 12, 2018

#### Explanation:

Note that:

Consider now the limit:

Substituting

So:

graph{sin(3x)/sin(2x) [-10, 10, -5, 5]}#

Jul 12, 2018

Note that:

Consider now the limit:

Substituting

So:

graph{sin(3x)/sin(2x) [-10, 10, -5, 5]}#