# Mg + Cl2 redox reaction explain?

## What is the substance being reduced and oxidised? What are the reducing and oxidising agents?

Dec 1, 2016

$M g \left(s\right) + C {l}_{2} \left(g\right) \rightarrow M g C {l}_{2} \left(s\right)$

#### Explanation:

The metal loses electrons, and in forming $M {g}^{2 +}$ it loses 2 electrons and is oxidized:

$M g \left(s\right) \rightarrow M {g}^{2 +} + 2 {e}^{-}$ $\left(i\right)$

And on the other hand chlorine is reduced to chloride ion by accepting electrons:

$C {l}_{2} \left(g\right) + 2 {e}^{-} \rightarrow 2 C {l}^{-}$ $\left(i i\right)$

And $\left(i\right) + \left(i i\right) =$ $M g \left(s\right) + C {l}_{2} \left(g\right) \rightarrow M g C {l}_{2} \left(s\right)$

Both charge and mass are balanced, as required.