# Milton and Bonnie are hiking. Milton averages 4 mph, and Bonnie averages 3 mph. If they start out together in the morning, but Milton gets to camp 2 hours and 30 minutes ahead of Bonnie, then how many miles did they hike that day?

Sep 15, 2015

I found $30 m$

#### Explanation:

Considering:
$v = \frac{d}{t}$ where $v$ is velocity, $d$ distance and $t$ time:
Milton does: $4 = \frac{d}{t}$
Bonnie does: $3 = \frac{d}{t + 2.5}$
Where 2h and 30 min correspond to $2.5 h$.
You get:
$4 t = 3 \left(t + 2.5\right)$
$4 t = 3 t + 7.5$
$t = 7.5 h$
Use it into the first equation:
$d = 4 t = 4 \cdot 7.5 = 30 m$