Question

Mole calculation problem? (Details below)

2.43g magnesium dissolves in excess dilute hydrochloric acid. The mass of hydrated magnesium chloride `(MgCl_2·6H_2O)` after crystallization is...
Thanks!

Answer 1

We assess the reaction....

`Mg(s) + 2HCl(aq) rarr MgCl_2 +H_2(g)uarr`

...and get approx. `20*g` of hydrated salt.

Explanation:

All of our calculations depend on the given stoichiometric equation. A follow up question would be to determine the volume of dihydrogen gas evolved under given conditions.

And so ........

`"moles of magnesium"-="moles of magnesium chloride hydrate"`

`"Moles of magnesium"-=(2.43*g)/(24.31*g*mol^-1)=0.100*mol`.

And so we get `0.100*mol` `"magnesium chloride hydrate"`, the which represents a mass of....

`0.100*molxxunderbrace(203.3*g*mol^-1)_("formula mass of "MgCl_2*6H_2O)=??*g`