# Near Room temperature air has a density of 1.18 x 10^-3 g/ml. What volume will 30.77 grams of air occupy?

##### 1 Answer
May 24, 2016

Approx. $26 \cdot L$

#### Explanation:

$\text{Density}$ $=$ $\text{Mass"/"Volume}$.

Thus $\text{Volume}$ $=$ $\text{Mass"/"Density}$

Now $\text{density, } \rho$ $=$ $1.18 \times {10}^{-} 3 \cdot g \cdot m {L}^{-} 1$.

And $\text{Volume}$ $=$ $\frac{30.77 \cdot g}{1.18 \times {10}^{-} 3 \cdot g \cdot m {L}^{-} 1}$ $=$ ??mL

Of course, $1000 \cdot m L = 1 \cdot L$