Niacin (#C_6NH_5O_2#) reacts with #O_2# to produce #CO_2#, #H_2O#, and #NO_2#. How would you write and balance the equation for this reaction?

1 Answer
Jul 7, 2016

Answer:

#4C_6NH_5O_2+29O_2->24CO_2+10H_2O+4NO_2#

Explanation:

After adjusting the no of atoms of 6C,1N and 5 H in RHS with LHS ,we get total #(14+5/2) # O at RHS.
To adjust the no of O atom in
LHS we can write #(6+5/4) #before #O_2# in LHS and the balanced equation becomes.

#C_6NH_5O_2+(6+5/4)O_2->6CO_2+5/2H_2O+NO_2#

Finally multiplying by 4 on both sides to remove fraction,we get the balanced equation as follows.

#4C_6NH_5O_2+29O_2->24CO_2+10H_2O+4NO_2#