# Niacin (C_6NH_5O_2) reacts with O_2 to produce CO_2, H_2O, and NO_2. How would you write and balance the equation for this reaction?

Jul 7, 2016

$4 {C}_{6} N {H}_{5} {O}_{2} + 29 {O}_{2} \to 24 C {O}_{2} + 10 {H}_{2} O + 4 N {O}_{2}$

#### Explanation:

After adjusting the no of atoms of 6C,1N and 5 H in RHS with LHS ,we get total $\left(14 + \frac{5}{2}\right)$ O at RHS.
To adjust the no of O atom in
LHS we can write $\left(6 + \frac{5}{4}\right)$before ${O}_{2}$ in LHS and the balanced equation becomes.

${C}_{6} N {H}_{5} {O}_{2} + \left(6 + \frac{5}{4}\right) {O}_{2} \to 6 C {O}_{2} + \frac{5}{2} {H}_{2} O + N {O}_{2}$

Finally multiplying by 4 on both sides to remove fraction,we get the balanced equation as follows.

$4 {C}_{6} N {H}_{5} {O}_{2} + 29 {O}_{2} \to 24 C {O}_{2} + 10 {H}_{2} O + 4 N {O}_{2}$