# Objects A and B are at the origin. If object A moves to (6 ,7 ) and object B moves to (-1 ,3 ) over 4 s, what is the relative velocity of object B from the perspective of object A?

Feb 14, 2018

First, use the Pythagorean Theorem, then use equation $d = v t$

#### Explanation:

Object A has moved c=sqrt(6^2+7^2=9.22m

Object B has moved c=sqrt((-1)^2+3^2=3.16m

The velocity of Object A is then $\frac{9.22 m}{4 s} = 2.31 \frac{m}{s}$

The velocity of Object B is then $\frac{3.16 m}{4 s} = .79 \frac{m}{s}$

Since these objects are moving in opposite directions, these velocities will add, so they will appear to be moving at 3.10 m/s
away from each other.