On a typical summer evening the temperature was 90°F at 7:00 PM. At 8:00 A.M. the next morning the temperature was 70.5 F. What is the average rate of change in temperature?

1 Answer
May 16, 2017

Answer:

#1.5 (""^oF)/(hr)#

Explanation:

I wouldn't necessarily call this a chemistry-related question, but it doesn't matter, I'll help.

The average rate of change of temperature with respect to time in this case can be represented by the equation

#(DeltaT^o)_(av) = (DeltaT^o)/(Deltat)#

where

#(DeltaT^o)_(av)# is the average rate of change of temperature with time,

#DeltaT^o# is the total change in temperature over the time period

and #Deltat# is the total change in time

The total change in temperature over the time period is

#90 ^oF - 70.5 ^oF = **19.5 ^oF** #

and the total time change is

#20:00# (for convenience) #- 7:00 = **13hr** #

Plugging values into the equation, we have

#(DeltaT^o)_(av) = (DeltaT^o)/(Deltat) = (19.5 ^oF)/(13hr) = 1.5 (""^oF)/(hr)#