Pam walks 7/8 of a mile to school. Paul walks 1/2 of a mile to school. How much farther does Pam walk than Paul?

1 Answer
Jan 6, 2017

Pam walks 3/8 of a mile further than Paul.

Explanation:

We can write a formula for this as:

$d = M - L$

Where:

$d$ is the difference in the walks
$M$ is the distance Pam walks
$L$ is the distance Paul walks.

Substituting the information from the problem gives:

$d = \frac{7}{8} - \frac{1}{2}$

In order to subtract or add fractions they need to be over a common denominator. For this problem the common denominator can be $8$. Therefore we need to ultiply $\frac{1}{2}$ by the appropriate form of $1$ to get this common denominator:

$d = \frac{7}{8} - \left(\frac{4}{4} \times \frac{1}{2}\right)$

$d = \frac{7}{8} - \frac{4 \times 1}{4 \times 2}$

$d = \frac{7}{8} - \frac{4}{8}$

We can now subtract these fractions:

$d = \frac{7 - 4}{8}$

$d = \frac{3}{8}$