PH of #0.1(N)CH_3COOH# is what?

1 Answer
Doc048
Jul 2, 2017

pH = 2.87

Explanation:

Acetic Acid => HOAc

0.10 Normal HOAc = 0.10 Molar HOAc

#K_a(HOAc) = 1.8xx10^-5#

#[H^+] = sqrt(K_a("HOAc")) = sqrt(1.8xx10^(-5)(0.10))# M = #0.0013M "in" H^+ions#

#pH = -log[H^+] = - log(0.0013)# = #-(-2.87) = 2.87#

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