PI3Br2 is a nonpolar molecule, how would you determine the bond angle of I-P-I bond , Br-P-Br bond and I-P-Br bond angles?
According to VSEPR theory, it must have a trigonal bipyramidal geometry.
There are three "equatorial" bonds in a trigonal planar arrangement and two "axial" bonds in a linear arrangement.
So, how are the five halogen atoms arranged in the molecule?
Since the molecule is nonpolar, the two
Also, the three
∴ The bond angles must be: