# Please help soon. Due tomorrow. Can anyone help me create a polynomial function with given zeros?

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The zeros are 2, 4 + *i*, 4 - *i*

The i is imaginary

I can get this far:

(x-2)(x-4+i)(x+4-i)

But I'm confused with the signs for the second and third sets of parenthesis. I'm not sure what signs are supposed to change or if I have them correct.

The zeros are 2, 4 + *i*, 4 - *i*

The i is imaginary

I can get this far:

(x-2)(x-4+i)(x+4-i)

But I'm confused with the signs for the second and third sets of parenthesis. I'm not sure what signs are supposed to change or if I have them correct.

##### 1 Answer

Dec 5, 2016

The zeros are

The factors are:

I would start by multiplying

# = x^2-4x+x i-4x - x i +(16-i^2)#

# = x^2-8x +(16-(-1))#

# = x^2-8x+17#

Note that I used the product of a sum and difference

Now multiply