# Please may somebody evaluate 13 to the power of -2?

Mar 7, 2018

You should do $13 \cdot 13$ and put that as the denominator of $1$.

#### Explanation:

Because ${13}^{- 2}$ has a negative exponent, you must divide one by it to make it positive.

$13 \cdot 13 = 169$

Divide one by this and you will get

$\frac{1}{169}$ or $\frac{1}{13} ^ 2$