Please solve q 96 ?

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1 Answer
Aug 1, 2018

Sorry don't know how to put a diagram on but using your sketch...

Explanation:

In #Delta#BEC :
#ChatBE=51^@# and #EhatCB=78^@# given, so #BhatEC=51^@#
This makes it isosceles with BC=CE

In #Delta#BCD :
#DhatBC=78^@# and #BhatCD=24^@# given, so #BhatDC=78^@#
This makes it isosceles with BC=DC

From this working CE=DC making #Delta#DEC isosceles too with #DhatCE=54^@# so #ChatDE=ChatED=63^@#

As #BhatEC=51^@# then #BhatED=63-51=12^@#

Option 3

Hope you can follow this!