Question

Precalculus math hw help?!

Answer 1

The answer is `[B]`.

Explanation:

Given `x=-tant` and `y=-sect`, where `-pi/2<=t<=pi/2`

at `t=0`, `x=0` and `y=-1` i.e. point `(0,-1)` lies on curve;

as `t->-pi/2` (from RHS), `x->oo` and `y->-oo` i.e. point `(oo,-oo)` and as `t` moves from `-pi/2` to `0`, point moves from `(oo,-oo)` to `(0,-1)` i.e. from `Q4` to to `(0,-1)` on `y`-axis

and as `t->pi/2` (from LHS), `x->-oo` and `y->-oo` i.e. point `(-oo,-oo)` and as `t` moves from `0` to `pi/2`, point moves from `(0,-1)` to `(-oo,-oo)` i.e. from `(0,-1)` on `y`-axis to `(-oo,-oo` in `Q3`

Hence answer is `[B]`.