Prove or disprove ? #f(A/B)=f(A)/f(B)#

1 Answer
Jun 12, 2017

This identity is generally false...

Explanation:

In general this will be false.

A simple example would be:

#f(x) = 2#

Then:

#f(1/1) = 2 != 1 = 2/2 = f(1)/f(1)#

#color(white)()#
Bonus

For what kind of functions #f(x)# does the identity hold?

Note that:

#f(1) = f(1/1) = f(1)/f(1) = 1#

#f(0) = f(0/x) = f(0)/f(x)" "# for any #x#

So either #f(0) = 0# or #f(x) = 1# for all #x#

If #n# is any integer and:

#f(x) = x^n#

Then:

#f(a/b) = (a/b)^n = a^n/b^n = f(a)/f(b)#

There are other possibilities for #f(x)#:

#f(x) = abs(x)^c" "# for any real constant #c#

#f(x) = "sgn"(x)*abs(x)^c" "# for any real constant #c#