Question

R = cot(`theta`) converted to rectangular form?

I come to `r^2*sin(theta)=r*cos(theta)`

Answer 1

`y^2 + y^4/x^2 = 1`

Explanation:

If we have

`r = cottheta`

We know that `tantheta = y/x`, and since `cottheta = 1/tantheta`, we get

`r = x/y`

Recall that `r = sqrt(x^2 + y^2)`

`sqrt(x^2 + y^2) = x/y`

`x^2 + y^2 = x^2/y^2`

`1+ y^2/x^2 = 1/y^2`

`y^2 + y^4/x^2 = 1`

Hopefully this helps!