# Review this reaction: H_2SO_4 + NaOH. What are th product(s)?

Apr 5, 2017

The products are ${H}_{2} O$ and $N {a}_{2} S {O}_{4}$, since this is a double-replacement/neutralization reaction.

#### Explanation:

This is a double-replacement neutralization (acid-base) reaction:

The two $H$ atoms in ${H}_{2} S {O}_{4}$ would react with the hydroxide ion, $O {H}^{-}$, in $N a O H$ to form water, ${H}_{2} O$.

The $S {O}_{4}$ would react with $N a$ to form $N {a}_{2} S {O}_{4}$ .

${H}_{2} S {O}_{4} + N a O H \to {H}_{2} O + N {a}_{2} S {O}_{4}$