Show that sin θ + i cos θ = cis π 2 − θ .?

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Answer 1 · 2018-01-19T09:52:07

Please see below.

#cisA=cosA+isinA#

Hence #cis(pi/2-theta)#

= #cos(pi/2-theta)+isin(pi/2-theta)#

= #sintheta+icostheta#

Show that sin θ + i cos θ = cis π 2 − θ  .?