#sin(alpha/2) = 1/4# and #405^@ < alpha/2 < 450^@#. Find #cosalpha#"?

Answer is #-(sqrt(8+2sqrt15))/4#.

Thanks in advance!

1 Answer
May 27, 2018

The interval #(405^@, 450^@)# is the same as the interval:
#(45^@, 90^@)#
#sin (a/2) = 1/4 = 0.25#
Calculator gives --> #a/2 = 14^@47#
The arc (a/2) isn't located in the above interval.
So the question should be corrected before solving.