Question

Solve tan x - sqrt3 = 0 on the interval [0,2pi)?

Answer 1

`x=1/3pi,4/3pi`

Explanation:

`tanx-sqrt3=0`

`rArr tanx=sqrt3`

`rArr x= arctansqrt3=1/3pi`

But `tanx` is periodic every `pi` radians, so `x=(1"/"3)pi+pi=(4"/"3)pi` is also an answer.