Solve the following pair of simultaneous equation by the elimination method? $x + 6 y = - 3$ $x+6y=-3$ , $3 x - 2 y = 11$ $3x - 2y=11$

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Answer 1 · 2018-05-05T23:23:38

$x = 3, y = - 1$ $x=3, y=-1$

Multiply the second equation by 3

$\Rightarrow 3 \times (3 x - 2 y = 11) . \Rightarrow 9 x - 6 y = 33$ $=> 3xx(3x-2y=11). => 9x-6y=33$

Now you have

$x + 6 y = - 3$ $x+6y=-3$
$9 x - 6 y = 33$ $9x-6y=33$

We have the same number of $y$ $y$ s, as they are different signs we add the two equations to remove the $y$ $y$ s

$10 x = 30$ $10x=30$

$x = 3$ $x=3$

Put $x = 3$ $x=3$ into $x + 6 y = - 3$ $x+6y=-3$

$\Rightarrow 3 + 6 y = - 3$ $=> 3+6y=-3$
$\Rightarrow 6 y = - 6$ $=> 6y=-6$
$\Rightarrow y = - 1$ $=> y=-1$

Solve the following pair of simultaneous equation by the elimination method? x+6y=-3x+6y=−3x+6y=-3, 3x - 2y=113x−2y=113x - 2y=11