Some help please question below ?

enter image source here

1 Answer
Al E.
May 24, 2018

If the data given is accurate, this is as simple as relating the molar enthalpy of reaction to the moles reacted.

#DeltaH_"rxn"^° = (-4163"kJ")/"mol"#

Hence, the heat released is,

#0.363"mol" * (-4163"kJ")/"mol" approx -1511"kJ"#

given your data.

Related questions
Impact of this question
973 views around the world
You can reuse this answer
Creative Commons License