Some very hot rocks have a temperature of $340^{o} C$ $340 ^o C$ and a specific heat of $160 \frac{J}{K g \cdot K}$ $160 J/(Kg*K)$ . The rocks are bathed in $72 L$ $72 L$ of boiling water. If the heat of the rocks completely vaporizes the water, what is the minimum combined mass of the rocks?

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Some very hot rocks have a temperature of $340^{o} C$ $340 ^o C$ and a specific heat of $160 \frac{J}{K g \cdot K}$ $160 J/(Kg*K)$ . The rocks are bathed in $72 L$ $72 L$ of boiling water. If the heat of the rocks completely vaporizes the water, what is the minimum combined mass of the rocks?

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Answer 1 · 2016-03-31T12:20:29

the minimum combined mass of the rocks are 4256. 25kg

Explanation:

the heat necessary to completely vaporizes the water is
$Q = m \cdot λ$ $Q=m*lamda$
$Q = 72 \cdot 2.27 \cdot 10^{6}$ $Q=72*2.27*10^6$
this heat due to the rock released
$Q = 72 \cdot 2.27 \cdot 10^{6} = m \cdot 160 \cdot (340 - 100)$ $Q=72*2.27*10^6=m*160*(340-100)$
$m = \frac{72 \cdot 2.27 \cdot 10^{6}}{160 \cdot 240}$ $m=(72*2.27*10^6)/(160*240)$
$m = 4256.25 k g$ $m=4256.25kg$

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Some very hot rocks have a temperature of $340^{o} C$ $340 ^o C$ and a specific heat of $160 \frac{J}{K g \cdot K}$ $160 J/(Kg*K)$ . The rocks are bathed in $72 L$ $72 L$ of boiling water. If the heat of the rocks completely vaporizes the water, what is the minimum combined mass of the rocks?

1 Answer

Explanation:

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Some very hot rocks have a temperature of 340oC340 ^o C and a specific heat of 160JKg⋅K160 J/(Kg*K). The rocks are bathed in 72L72 L of boiling water. If the heat of the rocks completely vaporizes the water, what is the minimum combined mass of the rocks?

1 Answer

Explanation:

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Impact of this question

Some very hot rocks have a temperature of $340^{o} C$ $340 ^o C$ and a specific heat of $160 \frac{J}{K g \cdot K}$ $160 J/(Kg*K)$ . The rocks are bathed in $72 L$ $72 L$ of boiling water. If the heat of the rocks completely vaporizes the water, what is the minimum combined mass of the rocks?