# Some very hot rocks have a temperature of 340 ^o C and a specific heat of 160 J/(Kg*K). The rocks are bathed in 72 L of boiling water. If the heat of the rocks completely vaporizes the water, what is the minimum combined mass of the rocks?

Mar 31, 2016

the minimum combined mass of the rocks are 4256. 25kg

#### Explanation:

the heat necessary to completely vaporizes the water is
$Q = m \cdot l a m \mathrm{da}$
$Q = 72 \cdot 2.27 \cdot {10}^{6}$
this heat due to the rock released
$Q = 72 \cdot 2.27 \cdot {10}^{6} = m \cdot 160 \cdot \left(340 - 100\right)$
$m = \frac{72 \cdot 2.27 \cdot {10}^{6}}{160 \cdot 240}$
$m = 4256.25 k g$