Question

Some very hot rocks have a temperature of `460 ^o C` and a specific heat of `64 J/(Kg*K)`. The rocks are bathed in `108 L` of boiling water. If the heat of the rocks completely vaporizes the water, what is the minimum combined mass of the rocks?

Answer 1

Let minimum combined mass be m kg
Mass of 108L water = 108 kg , taking density of water as `1000kgL^-1`
By calorimetric principle
`mxx64xx(430-100)=108xx540xx4200`
`m=(108xx540xx4200)/(360xx64)=10631.25kg`