Super confused need help asap. Am I right or am I losing my mind?

#(cos^2/sin^2X)(1/sin^2X)#

Doesn't this equal #cos^2x/sin^4x# I could've sworn someone told me to multiply the two denominators together or I might be going crazy. I need an answer asap.

1 Answer
Feb 6, 2018

That makes total sense what you did. Let's just check to see if we can somehow simplify further.

Recall that #cos^2x +sin^2x =1#:

#(1 - sin^2x)/sin^4x#

#1/sin^4x - 1/sin^2x#

#csc^4x - csc^2x#

Or we can rewrite as #cot^2xcsc^2x# because #cottheta = costheta/sintheta# and #cscx = 1/sinx#

Hopefully this helps!