# Suppose a car sitting on a hydraulic lift exerts a downward force of 1,750 N on a piston with an area of 0.6m^3. How much pressure does the car exert on the piston?

Dec 18, 2016

So, for a 1750 N force applied to 0.6 ${m}^{3}$, we find
$P = \frac{F}{A}$ = $\frac{1750 N}{0.6 {m}^{3}}$ = 2917 Pa or 2.917 kPa