Question

Suppose that its velocity function is given by `v(t) = 4t^2 -8t` where t is in seconds, how do you find the object's average acceleration along the time interval [3, 9] seconds?

Answer 1

Please see below.

Explanation:

The acceleration is the rate of change of velocity.

The average rate of change of a function `f` on an interval `[a,b]` is

`(f(b)-f(a))/(b-a)`

So, the average acceleration we have been asked for is

`(v(9)-v(3))/(9-3) = 40` (distance/sec/sec)