#### Explanation:

Continuous compound interest is where the exponential value of $e$ comes in.

Instead of using $P {\left(1 + \frac{x}{n \times 100}\right)}^{n}$ the bracketed part is replaced by $e \approx 2.7183$

So we have:

$5000 (e)^n But in this case $n$not just the count of years/cycles n=x%xxt" " where $t \to$count of years So $n = \frac{6.3}{100} \times 3 = \frac{18.9}{100}$giving: $5000(e)^(18.9/100) =$6040.2047...  $6040.20 to 2 decimal places