# Tate has bag of golf balls 3 red, 5 blue, 2 yellow, and 2 green. What is the probability that he pulls out a red one, replaces it, and then pulls out another red one?

Nov 3, 2016

$\frac{3}{12} \times \frac{3}{12} = \frac{1}{16}$

#### Explanation:

There are 12 golf balls, of which 3 are red.

The probability of drawing a red = $\frac{3}{12}$

The fact that the ball was replaced, means that the probability for drawing a red a second time is still $\frac{3}{12}$

$P \left(R R\right) = P \left(R\right) \times P \left(R\right) \text{ } \leftarrow$ read 'TIMES' as 'AND'

=$\frac{3}{12} \times \frac{3}{12} = \frac{1}{4} \times \frac{1}{4} = \frac{1}{16}$