The air in lungs has 0.153 mol of gas particles at 302 K and 101.3 kPa of pressure. What is the volume of the air?
1 Answer
May 13, 2016
3.79L
Explanation:
This can be solved applying equation of state for ideal gas, which i as follows
#PV=nRT#
Where for air in the lungs

#"Pressure" (P)= 101.3kPa = 1atm# 
#"No. of moles"(n)=0.153# 
#"Temperature"(T)=302K# 
#"Universal gas constant " (R)= 0.082Latm K^1mol^1# 
#"Volume of air" (V) =?#