# The base of an isosceles triangle is 5, the height lowered from one end of the base is 4. What is the surface area?

$10$
The area of any triangle is given by $\frac{1}{2} \cdot b \cdot h$ where $b$ is the base and $h$ is the hieght.
Therefore the area here is $\frac{1}{2} \cdot 5 \cdot 4 = 10$